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已知y1(X)与y2(x)是方程:y" + P(x)y"+Q(x)y = 0的两个线性无关的特解,y1(x)和y2(x)分别是方程y"+P(x)y"+Q(x)y=R1(x)和y"+p(x)+Q(x)y=R2(x)的特解。那么方程y"+p(x)y"+Q(x)y=R1(x)+R2(x)的通解应是:

单选题
已知y1(X)与y2(x)是方程:y" + P(x)y"+Q(x)y = 0的两个线性无关的特解,y1(x)和y2(x)分别是方程y"+P(x)y"+Q(x)y=R1(x)和y"+p(x)+Q(x)y=R2(x)的特解。那么方程y"+p(x)y"+Q(x)y=R1(x)+R2(x)的通解应是:

Ac1y1+c2y2

Bc1Y1(x) +c2Y2 (x)

Cc1y1+c2y2 +Y1(x)

Dc1y1+c2y2 +Y1 (x) +Y2 (x)

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